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9x^2-16x-3724=0
a = 9; b = -16; c = -3724;
Δ = b2-4ac
Δ = -162-4·9·(-3724)
Δ = 134320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{134320}=\sqrt{16*8395}=\sqrt{16}*\sqrt{8395}=4\sqrt{8395}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{8395}}{2*9}=\frac{16-4\sqrt{8395}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{8395}}{2*9}=\frac{16+4\sqrt{8395}}{18} $
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